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## LTSpice simulation ## LTSpice simulation
By modifying the $R_{cal1}$ resistor we can see that the maximum output voltage can go up to $5V$. The goal would be to modify this resistor value to have a maximum output of around $3.3V$: By modifying the $R_{cal1}$ resistor we can see that the maximum output voltage can go up to $5V$. The goal would be to modify this resistor value to have a maximum output of around $3.3V$:
#### Calculate $a$
$$a=\frac{\Delta{y}}{\Delta{x}}=\frac{y_2-y_1}{x_2-x_1}$$ $$a=\frac{\Delta{y}}{\Delta{x}}=\frac{y_2-y_1}{x_2-x_1}$$
$$AN: a=\frac{10k-1k}{2.1-4.94}$$ $$AN: a=\frac{10k-1k}{2.1-4.94}$$
$$AN: a=-3170$$ $$AN: a=-3170$$
--- #### Calculate $b$
$$y=-3170x+b$$ $$y=-3170x+b$$
$$1000=-3170(4.94)+b$$ $$1000=-3170(4.94)+b$$
$$b=3170(4.94)+1000$$ $$b=3170(4.94)+1000$$
$$b=16659$$ $$b=16659$$
--- #### Numerical Application
$$y=-3170x+16659$$ $$y=-3170x+16659$$
We can now calculate the resistor $R_{cal1}$ to have $3.3V$ in maximum output with the previous formula, we find: We can now calculate the resistor $R_{cal1}$ to have $3.3V$ in maximum output with the previous formula, we find:
$$-3.17\times{10^3\times{3.3V}}+16.7\times{10^3}=6.2k\Omega$$ $$-3.17\times{10^3\times{3.3V}}+16.7\times{10^3}=6.2k\Omega$$